What three consecutive integers have a sum of 6321?

Here we will use algebra to find three consecutive integers whose sum is 6321. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 6321. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 6321

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 6321
3X + 3 = 6321

3X + 3 - 3 = 6321 - 3
3X = 6318

3X/3 = 6318/3
X = 2106

Which means that the first number is 2106, the second number is 2106 + 1 and the third number is 2106 + 2. Therefore, three consecutive integers that add up to 6321 are 2106, 2107, and 2108.

2106 + 2107 + 2108 = 6321

We know our answer is correct because 2106 + 2107 + 2108 equals 6321 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 6322?
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