What three consecutive integers have a sum of 6468?

Here we will use algebra to find three consecutive integers whose sum is 6468. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 6468. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 6468

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 6468
3X + 3 = 6468

3X + 3 - 3 = 6468 - 3
3X = 6465

3X/3 = 6465/3
X = 2155

Which means that the first number is 2155, the second number is 2155 + 1 and the third number is 2155 + 2. Therefore, three consecutive integers that add up to 6468 are 2155, 2156, and 2157.

2155 + 2156 + 2157 = 6468

We know our answer is correct because 2155 + 2156 + 2157 equals 6468 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 6469?
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