What three consecutive integers have a sum of 6570?

Here we will use algebra to find three consecutive integers whose sum is 6570. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 6570. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 6570

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 6570
3X + 3 = 6570

3X + 3 - 3 = 6570 - 3
3X = 6567

3X/3 = 6567/3
X = 2189

Which means that the first number is 2189, the second number is 2189 + 1 and the third number is 2189 + 2. Therefore, three consecutive integers that add up to 6570 are 2189, 2190, and 2191.

2189 + 2190 + 2191 = 6570

We know our answer is correct because 2189 + 2190 + 2191 equals 6570 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 6571?
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