What three consecutive integers have a sum of 6615?

Here we will use algebra to find three consecutive integers whose sum is 6615. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 6615. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 6615

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 6615
3X + 3 = 6615

3X + 3 - 3 = 6615 - 3
3X = 6612

3X/3 = 6612/3
X = 2204

Which means that the first number is 2204, the second number is 2204 + 1 and the third number is 2204 + 2. Therefore, three consecutive integers that add up to 6615 are 2204, 2205, and 2206.

2204 + 2205 + 2206 = 6615

We know our answer is correct because 2204 + 2205 + 2206 equals 6615 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 6616?
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