What three consecutive integers have a sum of 6687?

Here we will use algebra to find three consecutive integers whose sum is 6687. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 6687. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 6687

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 6687
3X + 3 = 6687

3X + 3 - 3 = 6687 - 3
3X = 6684

3X/3 = 6684/3
X = 2228

Which means that the first number is 2228, the second number is 2228 + 1 and the third number is 2228 + 2. Therefore, three consecutive integers that add up to 6687 are 2228, 2229, and 2230.

2228 + 2229 + 2230 = 6687

We know our answer is correct because 2228 + 2229 + 2230 equals 6687 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 6688?
Here is the next algebra problem we solved.