What three consecutive integers have a sum of 6987?

Here we will use algebra to find three consecutive integers whose sum is 6987. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 6987. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 6987

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 6987
3X + 3 = 6987

3X + 3 - 3 = 6987 - 3
3X = 6984

3X/3 = 6984/3
X = 2328

Which means that the first number is 2328, the second number is 2328 + 1 and the third number is 2328 + 2. Therefore, three consecutive integers that add up to 6987 are 2328, 2329, and 2330.

2328 + 2329 + 2330 = 6987

We know our answer is correct because 2328 + 2329 + 2330 equals 6987 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 6988?
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