What three consecutive integers have a sum of 699?

Here we will use algebra to find three consecutive integers whose sum is 699. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 699. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 699

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 699
3X + 3 = 699

3X + 3 - 3 = 699 - 3
3X = 696

3X/3 = 696/3
X = 232

Which means that the first number is 232, the second number is 232 + 1 and the third number is 232 + 2. Therefore, three consecutive integers that add up to 699 are 232, 233, and 234.

232 + 233 + 234 = 699

We know our answer is correct because 232 + 233 + 234 equals 699 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

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