What three consecutive integers have a sum of 702?

Here we will use algebra to find three consecutive integers whose sum is 702. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 702. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 702

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 702
3X + 3 = 702

3X + 3 - 3 = 702 - 3
3X = 699

3X/3 = 699/3
X = 233

Which means that the first number is 233, the second number is 233 + 1 and the third number is 233 + 2. Therefore, three consecutive integers that add up to 702 are 233, 234, and 235.

233 + 234 + 235 = 702

We know our answer is correct because 233 + 234 + 235 equals 702 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 703?
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