What three consecutive integers have a sum of 7032?

Here we will use algebra to find three consecutive integers whose sum is 7032. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 7032. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 7032

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 7032
3X + 3 = 7032

3X + 3 - 3 = 7032 - 3
3X = 7029

3X/3 = 7029/3
X = 2343

Which means that the first number is 2343, the second number is 2343 + 1 and the third number is 2343 + 2. Therefore, three consecutive integers that add up to 7032 are 2343, 2344, and 2345.

2343 + 2344 + 2345 = 7032

We know our answer is correct because 2343 + 2344 + 2345 equals 7032 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 7033?
Here is the next algebra problem we solved.