What three consecutive integers have a sum of 7074?

Here we will use algebra to find three consecutive integers whose sum is 7074. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 7074. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 7074

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 7074
3X + 3 = 7074

3X + 3 - 3 = 7074 - 3
3X = 7071

3X/3 = 7071/3
X = 2357

Which means that the first number is 2357, the second number is 2357 + 1 and the third number is 2357 + 2. Therefore, three consecutive integers that add up to 7074 are 2357, 2358, and 2359.

2357 + 2358 + 2359 = 7074

We know our answer is correct because 2357 + 2358 + 2359 equals 7074 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 7075?
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