What three consecutive integers have a sum of 717?

Here we will use algebra to find three consecutive integers whose sum is 717. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 717. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 717

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 717
3X + 3 = 717

3X + 3 - 3 = 717 - 3
3X = 714

3X/3 = 714/3
X = 238

Which means that the first number is 238, the second number is 238 + 1 and the third number is 238 + 2. Therefore, three consecutive integers that add up to 717 are 238, 239, and 240.

238 + 239 + 240 = 717

We know our answer is correct because 238 + 239 + 240 equals 717 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 718?
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