What three consecutive integers have a sum of 7215?

Here we will use algebra to find three consecutive integers whose sum is 7215. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 7215. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 7215

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 7215
3X + 3 = 7215

3X + 3 - 3 = 7215 - 3
3X = 7212

3X/3 = 7212/3
X = 2404

Which means that the first number is 2404, the second number is 2404 + 1 and the third number is 2404 + 2. Therefore, three consecutive integers that add up to 7215 are 2404, 2405, and 2406.

2404 + 2405 + 2406 = 7215

We know our answer is correct because 2404 + 2405 + 2406 equals 7215 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 7216?
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