What three consecutive integers have a sum of 747?

Here we will use algebra to find three consecutive integers whose sum is 747. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 747. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 747

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 747
3X + 3 = 747

3X + 3 - 3 = 747 - 3
3X = 744

3X/3 = 744/3
X = 248

Which means that the first number is 248, the second number is 248 + 1 and the third number is 248 + 2. Therefore, three consecutive integers that add up to 747 are 248, 249, and 250.

248 + 249 + 250 = 747

We know our answer is correct because 248 + 249 + 250 equals 747 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 748?
Here is the next algebra problem we solved.