What three consecutive integers have a sum of 750?

Here we will use algebra to find three consecutive integers whose sum is 750. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 750. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 750

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 750
3X + 3 = 750

3X + 3 - 3 = 750 - 3
3X = 747

3X/3 = 747/3
X = 249

Which means that the first number is 249, the second number is 249 + 1 and the third number is 249 + 2. Therefore, three consecutive integers that add up to 750 are 249, 250, and 251.

249 + 250 + 251 = 750

We know our answer is correct because 249 + 250 + 251 equals 750 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

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