What three consecutive integers have a sum of 753?




Here we will use algebra to find three consecutive integers whose sum is 753. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 753. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 753


To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 753
3X + 3 = 753

3X + 3 - 3 = 753 - 3
3X = 750

3X/3 = 750/3
X = 250

Which means that the first number is 250, the second number is 250 + 1 and the third number is 250 + 2. Therefore, three consecutive integers that add up to 753 are 250, 251, and 252.

250 + 251 + 252 = 753

We know our answer is correct because 250 + 251 + 252 equals 753 as displayed above.


Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.




What three consecutive integers have a sum of 754?
Here is the next algebra problem we solved.




Copyright  |   Privacy Policy  |   Disclaimer  |   Contact