What three consecutive integers have a sum of 7758?




Here we will use algebra to find three consecutive integers whose sum is 7758. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 7758. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 7758


To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 7758
3X + 3 = 7758

3X + 3 - 3 = 7758 - 3
3X = 7755

3X/3 = 7755/3
X = 2585

Which means that the first number is 2585, the second number is 2585 + 1 and the third number is 2585 + 2. Therefore, three consecutive integers that add up to 7758 are 2585, 2586, and 2587.

2585 + 2586 + 2587 = 7758

We know our answer is correct because 2585 + 2586 + 2587 equals 7758 as displayed above.


Three Consecutive Integers
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What three consecutive integers have a sum of 7759?
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