What three consecutive integers have a sum of 7803?

Here we will use algebra to find three consecutive integers whose sum is 7803. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 7803. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 7803

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 7803
3X + 3 = 7803

3X + 3 - 3 = 7803 - 3
3X = 7800

3X/3 = 7800/3
X = 2600

Which means that the first number is 2600, the second number is 2600 + 1 and the third number is 2600 + 2. Therefore, three consecutive integers that add up to 7803 are 2600, 2601, and 2602.

2600 + 2601 + 2602 = 7803

We know our answer is correct because 2600 + 2601 + 2602 equals 7803 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 7804?
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