What three consecutive integers have a sum of 7815?

Here we will use algebra to find three consecutive integers whose sum is 7815. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 7815. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 7815

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 7815
3X + 3 = 7815

3X + 3 - 3 = 7815 - 3
3X = 7812

3X/3 = 7812/3
X = 2604

Which means that the first number is 2604, the second number is 2604 + 1 and the third number is 2604 + 2. Therefore, three consecutive integers that add up to 7815 are 2604, 2605, and 2606.

2604 + 2605 + 2606 = 7815

We know our answer is correct because 2604 + 2605 + 2606 equals 7815 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 7816?
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