What three consecutive integers have a sum of 7962?

Here we will use algebra to find three consecutive integers whose sum is 7962. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 7962. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 7962

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 7962
3X + 3 = 7962

3X + 3 - 3 = 7962 - 3
3X = 7959

3X/3 = 7959/3
X = 2653

Which means that the first number is 2653, the second number is 2653 + 1 and the third number is 2653 + 2. Therefore, three consecutive integers that add up to 7962 are 2653, 2654, and 2655.

2653 + 2654 + 2655 = 7962

We know our answer is correct because 2653 + 2654 + 2655 equals 7962 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 7963?
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