What three consecutive integers have a sum of 7968?

Here we will use algebra to find three consecutive integers whose sum is 7968. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 7968. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 7968

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 7968
3X + 3 = 7968

3X + 3 - 3 = 7968 - 3
3X = 7965

3X/3 = 7965/3
X = 2655

Which means that the first number is 2655, the second number is 2655 + 1 and the third number is 2655 + 2. Therefore, three consecutive integers that add up to 7968 are 2655, 2656, and 2657.

2655 + 2656 + 2657 = 7968

We know our answer is correct because 2655 + 2656 + 2657 equals 7968 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 7969?
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