What three consecutive integers have a sum of 8115?

Here we will use algebra to find three consecutive integers whose sum is 8115. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 8115. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 8115

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 8115
3X + 3 = 8115

3X + 3 - 3 = 8115 - 3
3X = 8112

3X/3 = 8112/3
X = 2704

Which means that the first number is 2704, the second number is 2704 + 1 and the third number is 2704 + 2. Therefore, three consecutive integers that add up to 8115 are 2704, 2705, and 2706.

2704 + 2705 + 2706 = 8115

We know our answer is correct because 2704 + 2705 + 2706 equals 8115 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 8116?
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