What three consecutive integers have a sum of 8118?

Here we will use algebra to find three consecutive integers whose sum is 8118. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 8118. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 8118

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 8118
3X + 3 = 8118

3X + 3 - 3 = 8118 - 3
3X = 8115

3X/3 = 8115/3
X = 2705

Which means that the first number is 2705, the second number is 2705 + 1 and the third number is 2705 + 2. Therefore, three consecutive integers that add up to 8118 are 2705, 2706, and 2707.

2705 + 2706 + 2707 = 8118

We know our answer is correct because 2705 + 2706 + 2707 equals 8118 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 8119?
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