What three consecutive integers have a sum of 8217?

Here we will use algebra to find three consecutive integers whose sum is 8217. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 8217. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 8217

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 8217
3X + 3 = 8217

3X + 3 - 3 = 8217 - 3
3X = 8214

3X/3 = 8214/3
X = 2738

Which means that the first number is 2738, the second number is 2738 + 1 and the third number is 2738 + 2. Therefore, three consecutive integers that add up to 8217 are 2738, 2739, and 2740.

2738 + 2739 + 2740 = 8217

We know our answer is correct because 2738 + 2739 + 2740 equals 8217 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 8218?
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