What three consecutive integers have a sum of 8223?

Here we will use algebra to find three consecutive integers whose sum is 8223. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 8223. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 8223

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 8223
3X + 3 = 8223

3X + 3 - 3 = 8223 - 3
3X = 8220

3X/3 = 8220/3
X = 2740

Which means that the first number is 2740, the second number is 2740 + 1 and the third number is 2740 + 2. Therefore, three consecutive integers that add up to 8223 are 2740, 2741, and 2742.

2740 + 2741 + 2742 = 8223

We know our answer is correct because 2740 + 2741 + 2742 equals 8223 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 8224?
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