What three consecutive integers have a sum of 8487?

Here we will use algebra to find three consecutive integers whose sum is 8487. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 8487. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 8487

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 8487
3X + 3 = 8487

3X + 3 - 3 = 8487 - 3
3X = 8484

3X/3 = 8484/3
X = 2828

Which means that the first number is 2828, the second number is 2828 + 1 and the third number is 2828 + 2. Therefore, three consecutive integers that add up to 8487 are 2828, 2829, and 2830.

2828 + 2829 + 2830 = 8487

We know our answer is correct because 2828 + 2829 + 2830 equals 8487 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 8488?
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