What three consecutive integers have a sum of 8493?

Here we will use algebra to find three consecutive integers whose sum is 8493. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 8493. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 8493

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 8493
3X + 3 = 8493

3X + 3 - 3 = 8493 - 3
3X = 8490

3X/3 = 8490/3
X = 2830

Which means that the first number is 2830, the second number is 2830 + 1 and the third number is 2830 + 2. Therefore, three consecutive integers that add up to 8493 are 2830, 2831, and 2832.

2830 + 2831 + 2832 = 8493

We know our answer is correct because 2830 + 2831 + 2832 equals 8493 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 8494?
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