What three consecutive integers have a sum of 8649?

Here we will use algebra to find three consecutive integers whose sum is 8649. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 8649. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 8649

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 8649
3X + 3 = 8649

3X + 3 - 3 = 8649 - 3
3X = 8646

3X/3 = 8646/3
X = 2882

Which means that the first number is 2882, the second number is 2882 + 1 and the third number is 2882 + 2. Therefore, three consecutive integers that add up to 8649 are 2882, 2883, and 2884.

2882 + 2883 + 2884 = 8649

We know our answer is correct because 2882 + 2883 + 2884 equals 8649 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 8650?
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