What three consecutive integers have a sum of 8871?

Here we will use algebra to find three consecutive integers whose sum is 8871. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 8871. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 8871

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 8871
3X + 3 = 8871

3X + 3 - 3 = 8871 - 3
3X = 8868

3X/3 = 8868/3
X = 2956

Which means that the first number is 2956, the second number is 2956 + 1 and the third number is 2956 + 2. Therefore, three consecutive integers that add up to 8871 are 2956, 2957, and 2958.

2956 + 2957 + 2958 = 8871

We know our answer is correct because 2956 + 2957 + 2958 equals 8871 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 8872?
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