What three consecutive integers have a sum of 9330?

Here we will use algebra to find three consecutive integers whose sum is 9330. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 9330. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 9330

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 9330
3X + 3 = 9330

3X + 3 - 3 = 9330 - 3
3X = 9327

3X/3 = 9327/3
X = 3109

Which means that the first number is 3109, the second number is 3109 + 1 and the third number is 3109 + 2. Therefore, three consecutive integers that add up to 9330 are 3109, 3110, and 3111.

3109 + 3110 + 3111 = 9330

We know our answer is correct because 3109 + 3110 + 3111 equals 9330 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 9331?
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