What three consecutive integers have a sum of 9345?

Here we will use algebra to find three consecutive integers whose sum is 9345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 9345. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 9345

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 9345
3X + 3 = 9345

3X + 3 - 3 = 9345 - 3
3X = 9342

3X/3 = 9342/3
X = 3114

Which means that the first number is 3114, the second number is 3114 + 1 and the third number is 3114 + 2. Therefore, three consecutive integers that add up to 9345 are 3114, 3115, and 3116.

3114 + 3115 + 3116 = 9345

We know our answer is correct because 3114 + 3115 + 3116 equals 9345 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 9346?
Here is the next algebra problem we solved.