What three consecutive integers have a sum of 9360?

Here we will use algebra to find three consecutive integers whose sum is 9360. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 9360. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 9360

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 9360
3X + 3 = 9360

3X + 3 - 3 = 9360 - 3
3X = 9357

3X/3 = 9357/3
X = 3119

Which means that the first number is 3119, the second number is 3119 + 1 and the third number is 3119 + 2. Therefore, three consecutive integers that add up to 9360 are 3119, 3120, and 3121.

3119 + 3120 + 3121 = 9360

We know our answer is correct because 3119 + 3120 + 3121 equals 9360 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 9361?
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