What three consecutive integers have a sum of 9438?

Here we will use algebra to find three consecutive integers whose sum is 9438. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 9438. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 9438

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 9438
3X + 3 = 9438

3X + 3 - 3 = 9438 - 3
3X = 9435

3X/3 = 9435/3
X = 3145

Which means that the first number is 3145, the second number is 3145 + 1 and the third number is 3145 + 2. Therefore, three consecutive integers that add up to 9438 are 3145, 3146, and 3147.

3145 + 3146 + 3147 = 9438

We know our answer is correct because 3145 + 3146 + 3147 equals 9438 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 9439?
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