What three consecutive integers have a sum of 9465?

Here we will use algebra to find three consecutive integers whose sum is 9465. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 9465. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 9465

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 9465
3X + 3 = 9465

3X + 3 - 3 = 9465 - 3
3X = 9462

3X/3 = 9462/3
X = 3154

Which means that the first number is 3154, the second number is 3154 + 1 and the third number is 3154 + 2. Therefore, three consecutive integers that add up to 9465 are 3154, 3155, and 3156.

3154 + 3155 + 3156 = 9465

We know our answer is correct because 3154 + 3155 + 3156 equals 9465 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 9466?
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