What three consecutive integers have a sum of 9504?

Here we will use algebra to find three consecutive integers whose sum is 9504. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 9504. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 9504

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 9504
3X + 3 = 9504

3X + 3 - 3 = 9504 - 3
3X = 9501

3X/3 = 9501/3
X = 3167

Which means that the first number is 3167, the second number is 3167 + 1 and the third number is 3167 + 2. Therefore, three consecutive integers that add up to 9504 are 3167, 3168, and 3169.

3167 + 3168 + 3169 = 9504

We know our answer is correct because 3167 + 3168 + 3169 equals 9504 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 9505?
Here is the next algebra problem we solved.