What three consecutive integers have a sum of 9588?

Here we will use algebra to find three consecutive integers whose sum is 9588. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 9588. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 9588

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 9588
3X + 3 = 9588

3X + 3 - 3 = 9588 - 3
3X = 9585

3X/3 = 9585/3
X = 3195

Which means that the first number is 3195, the second number is 3195 + 1 and the third number is 3195 + 2. Therefore, three consecutive integers that add up to 9588 are 3195, 3196, and 3197.

3195 + 3196 + 3197 = 9588

We know our answer is correct because 3195 + 3196 + 3197 equals 9588 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 9589?
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