What three consecutive integers have a sum of 9606?

Here we will use algebra to find three consecutive integers whose sum is 9606. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 9606. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 9606

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 9606
3X + 3 = 9606

3X + 3 - 3 = 9606 - 3
3X = 9603

3X/3 = 9603/3
X = 3201

Which means that the first number is 3201, the second number is 3201 + 1 and the third number is 3201 + 2. Therefore, three consecutive integers that add up to 9606 are 3201, 3202, and 3203.

3201 + 3202 + 3203 = 9606

We know our answer is correct because 3201 + 3202 + 3203 equals 9606 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 9607?
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