What three consecutive integers have a sum of 9678?

Here we will use algebra to find three consecutive integers whose sum is 9678. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 9678. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 9678

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 9678
3X + 3 = 9678

3X + 3 - 3 = 9678 - 3
3X = 9675

3X/3 = 9675/3
X = 3225

Which means that the first number is 3225, the second number is 3225 + 1 and the third number is 3225 + 2. Therefore, three consecutive integers that add up to 9678 are 3225, 3226, and 3227.

3225 + 3226 + 3227 = 9678

We know our answer is correct because 3225 + 3226 + 3227 equals 9678 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 9679?
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